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JEE Advanced · Physics · 17. Electrostatics

Positive and negative point charges of equal magnitude are kept at \(\left(0,0, \frac{a}{2}\right)\) and \(\left(0,0, \frac{-a}{2}\right)\), respectively. The work done by the electric field when another positive point charge is moved from \((-a, 0,0)\) to \((0, a, 0)\) is

  1. A positive
  2. B negative
  3. C zero
  4. D depends on the path connecting the initial and final positions
Verified Solution

Answer & Solution

Correct Answer

(C) zero

Step-by-step Solution

Detailed explanation

\(A \equiv(-a, 0,0) B \equiv(0, a, 0)\)
Point charge is moved from \(A\) to \(B\)
\(
\begin{aligned}
V_A & =V_B=0 \\
W & =0
\end{aligned}
\)
\(
\therefore \quad W=0
\)
or the correct option is (c).

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