JEE Advanced · Chemistry · 9. Redox Reactions
Paragraph:
Redox reaction play a pivotal role in chemistry and biology. The values of standard redox potential \(\left(E^{\circ}\right)\) of two half-cell reactions decide which way the reaction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. Given below are a set of half-cell reactions (acidic medium) along with their \(E^{\circ}(V\) with respect to normal hydrogen electrode) values. Using this data obtain the correct explanations to Questions 14-19.
\(\mathrm{I}_2+2 e^{-} \longrightarrow 2 \mathrm{I}^{-} E^{\circ}=0.54 \)
\( \mathrm{Cl}_2+2 e^{-} \longrightarrow 2 \mathrm{Cl}^{-} E^{\circ}=1.36 \)
\( \mathrm{Mn}^{3+}+e^{-} \longrightarrow \mathrm{Mn}^{2+} E^{\circ}=1.50 \)
\( \mathrm{Fe}^{3+}+e^{-} \longrightarrow \mathrm{Fe}^{2+} E^{\circ}=0.77 \)
\( \mathrm{O}_2+4 \mathrm{H}^{+}+4 e^{-} \longrightarrow 2 \mathrm{H}_2 \mathrm{O} E^{\circ}=1.23\)
Question:
Among the following, identify the correct statement
- A Chloride ion is oxidised by \(\mathrm{O}_2\)
- B \(\mathrm{Fe}^{2+}\) is oxidised by iodine
- C Iodide ion is oxidised by chlorine
- D \(\mathrm{Mn}^{2+}\) is oxidised by chlorine
Answer & Solution
Correct Answer
(C) Iodide ion is oxidised by chlorine
Step-by-step Solution
Detailed explanation
\(2 \mathrm{I}^{-}+\mathrm{Cl}_2 \longrightarrow \mathrm{I}_2+2 \mathrm{Cl}^{-}\)
\(
E_{\text {cell }}^{\circ}=1.36-0.54=0.82 \mathrm{~V}
\)
\(E_{\text {cell }}^{\circ}\) is \(+v e\) cell reactions is feasible.
\(
E_{\text {cell }}^{\circ}=1.36-0.54=0.82 \mathrm{~V}
\)
\(E_{\text {cell }}^{\circ}\) is \(+v e\) cell reactions is feasible.
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