JEE Advanced · Physics · 17. Electrostatics
Paragraph:
The nuclear charge \((\mathrm{Ze})\) is non-uniformly distributed within a nucleus of radius \(R\). The charge density \(\rho(r)\) [charge per unit volume] is dependent only on the radial distance \(r\) from the centre of the nucleus as shown in figure. The electric field is only along the radial direction.

Question:
The electric field at \(r=R\) is
- A independent of \(a\)
- B directly proportional to \(a\)
- C directly proportional to \(a^2\)
- D inversely proportional to \(a\)
Answer & Solution
Correct Answer
(A) independent of \(a\)
Step-by-step Solution
Detailed explanation
At \(r=R\), from Gauss's law
or
\(
\begin{aligned}
E\left(4 \pi R^2\right) & =\frac{q_{\text {net }}}{\varepsilon_0}=\frac{Z e}{\varepsilon_0} \\
E & =\frac{1}{4 \pi \varepsilon_0} \cdot \frac{Z e}{R^2}
\end{aligned}
\)
\(E\) is independent of ' \(a\) '
\(\therefore\) correct option is (a).
or
\(
\begin{aligned}
E\left(4 \pi R^2\right) & =\frac{q_{\text {net }}}{\varepsilon_0}=\frac{Z e}{\varepsilon_0} \\
E & =\frac{1}{4 \pi \varepsilon_0} \cdot \frac{Z e}{R^2}
\end{aligned}
\)
\(E\) is independent of ' \(a\) '
\(\therefore\) correct option is (a).
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