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JEE Advanced · Physics · 13. Thermodynamics

One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the PV - diagram below. Among these four processes, one is isobaric, one is isochoric, one is isothermal and one is adiabatic. Match the processes mentioned in List-1 with the corresponding statements in List-II.
LIST -I LIST -II
A)In process IP)Work done by the gas is zero
B)In process IIQ)Temperature of the gas remains unchanged
C)In process IIIR)No heat is exchanged between the gas and its surroundings
D)In process IVS)Work done by the gas is 6P0V0

  1. A a-q;b-r;c-s;d-p;
  2. B a-r;b-p;c-s;d-q;
  3. C a-r;b-s;c-p;d-q;
  4. D a-p;b-s;c-q;d-r;
Verified Solution

Answer & Solution

Correct Answer

(C) a-r;b-s;c-p;d-q;

Step-by-step Solution

Detailed explanation

Process - I is an adiabatic process
Q=U+W
Q=0
W=-U
Volume of gas is decreasing  W < 0
U>0
   Temperatuer of gas increases
No heat is exchanged between the gas and surrounding.
Process - II  is an isobaric process
(Pressure remain constant)
W=P V=3P03V0-V0=6P0V0
Process - III is an isochoric process
(Volume remain constant)
Q=U+W
W=0
Q=U
Process - IV is an isothermal process
(Temperature remains constant)
Q=U+W
U=0
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