JEE Advanced · Physics · 17. Electrostatics
For spherical symmetrical charge distribution, variation of electric potential with distance from centre is given in diagram. Given that:
\(V=\frac{q}{4 \pi \varepsilon_0 R_0} \text { for } r \leq R_0\)
and \(V=\frac{q}{4 \pi \varepsilon_0 r}\) for \(r \geq R_0\)
Then which option(s) are correct
- A Total charge within \(2 R_0\) is \(q\)
- B Total electrostatic energy for \(r \leq R_0\) is zero
- C At \(r=R_0\) electric field is discontinuous
- D None of these
Answer & Solution
Correct Answer
(D) None of these
Step-by-step Solution
Detailed explanation
The given graph is of charged conducting sphere of radius \(R_0\). The whole charge \(q\) distributes on the surface of the sphere.
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