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JEE Advanced · Physics · 8. Rotational Motion

At time t=0, a disk of radius 1 m starts to roll without slipping on a horizontal plane with an angular acceleration of α=23 rad s-2. A small stone is stuck to the disk. At t=0, it is at the contact point of the disk and the plane. Later, at time t=π s, the stone detaches itself and flies off tangentially from the disk. The maximum height (in m) reached by the stone measured from the plane is 12+x10. The value of x is [Take g=10 m s-2.] If the numerical value has more than two decimal places, truncate/round-off the value to TWO decimal places.

  1. A 0.52
  2. B 0.55
  3. C 0.57
  4. D 0.59
Verified Solution

Answer & Solution

Correct Answer

(A) 0.52

Step-by-step Solution

Detailed explanation

Using second equation of motion, The angle rotated by disc in t=π s is θ=ω0t+12αt2
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