JEE Advanced · Physics · 5. Laws of Motion
A wire, which passes through the hole in a small bead, is bent in the form of quarter of a circle. The wire is fixed vertically on ground as shown in the figure. The bead is released from near the top of the wire and it slides along the wire without friction. As the bead moves from A to B, the force it applies on the wire is
- A always radially outwards.
- B always radially inwards.
- C radially outwards initially and radially inwards later.
- D radially inwards initially and radially outwards later.
Answer & Solution
Correct Answer
(D) radially inwards initially and radially outwards later.
Step-by-step Solution
Detailed explanation
Initially bead is applying radially inward normal force.
During motion at an instant, N = 0, after that N will act radially outward.
During motion at an instant, N = 0, after that N will act radially outward.
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