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JEE Advanced · Physics · 6. Work Power Energy

The work done on a particle of mass m by a force  K x x 2 + y 2 3 / 2 i ^ + y x 2 + y 2 3 / 2 j ^  (K being a constant of appropriate dimensions, when the particle is taken from the point (a,0) to the point (0,a) along a circular path of radius a about the origin in the x-y plane is

  1. A 2 K π a
  2. B K π a
  3. C K π 2 a
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(D) 0

Step-by-step Solution

Detailed explanation

\(d w==\vec{F} \cdot d \vec{r}=\vec{F} \cdot(d x \hat{i}+d y \hat{j})=K \int\) \(\frac{x d x}{\left(x^2+y^2\right)^{3 / 2}}+\frac{y d y}{\left(x^2+y^2\right)^{3 / 2}}\)
\(x^2+y^2=a^2\)
\(w =\frac{ K }{ a ^3} \int_{ a }^0 xdx +\int_0^{ a } ydy =\frac{ K }{ a ^3}\left(\frac{- a ^2}{2}+\frac{ a ^2}{2}\right)=0\).
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