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JEE Advanced · Physics · 5. Laws of Motion

A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m=0.4kg is at rest on this surface. An impulse of 1.0 N s is applied to the block at time t=0 so that it starts moving along the x-axis with a velocity vt=v0e-tτ , where v0 is a constant and τ=4 . The displacement of the block, in meter, at t=τ is __________. Take e-1=0.37

  1. A 6.3
  2. B 6.32
  3. C 6.34
  4. D 6.36
Verified Solution

Answer & Solution

Correct Answer

(A) 6.3

Step-by-step Solution

Detailed explanation


v=v0e-tτ
v0=Jm=2.5 m/s
v=v0e-tτ
dxdt=v0e-tτ
0xdx=v00τe-tτdt
e-xdx=e-x-1
x=v0e-tτ-1τ0τ
x=2.5-4e-1-e0
x=25-40.37-1
x=6.30
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