ExamBro
ExamBro
JEE Advanced · Physics · 24. Ray Optics

A beaker of radius r is filled with waterrefractive index 43 up to a height H as shown in the figure on the left. The beaker is kept on a horizontal table rotating with angular speed ω. This makes the water surface curved so that the difference in the height of water level at the centre and at the circumference of the beaker is hhH, hr, as shown in the figure on the right. Take this surface to be approximately spherical with a radius of curvature R. Which of the following is/are correct? (g is the acceleration due to gravity)

  1. A R=h2+r22h
  2. B R=3r22h
  3. C Apparent depth of the bottom of the beaker is close to 3H21+ω2H2g-1
  4. D Apparent depth of the bottom of the beaker is close to 3H41+ω2H4g-1
Verified Solution

Answer & Solution

Correct Answer

(D) Apparent depth of the bottom of the beaker is close to 3H41+ω2H4g-1

Step-by-step Solution

Detailed explanation

h=ω2r22g r2+(R-h)2=R2
Same subject
Explore more questions on app
From JEE Advanced
Explore more questions on app