JEE Advanced · Mathematics · 2. Quadratic Equations
Paragraph:
Let \(p, q\) be integers and let \(\alpha, \beta\) be the roots of the equation, \(x^{2}-x-1=0\), where \(\alpha \neq \beta\). For \(n=0,1,2, \ldots\), let \(a_{n}=p \alpha^{n}+q \beta^{n}\)
FACT: If \(a\) and \(b\) are rational numbers and \(a+b \sqrt{5}=0\), then \(a=0=b\).
Question:
\(a_{12}=\)
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
\(\alpha^2=\alpha+1 \Rightarrow \alpha^n=\alpha^{n-1}+\alpha^{ n -2}\)
\(\Rightarrow p \alpha^n+q \beta^n=p\left(\alpha^{n-1}+\alpha^{n-2}\right)+ q\) \(\left(\beta^{n-1}+\beta^{n-2}\right)\)
\(a_n=a_{n-1}+a_{ n -2}\)
\(\Rightarrow a_{12}=a_{11}+a_{10}\)
\(\Rightarrow p \alpha^n+q \beta^n=p\left(\alpha^{n-1}+\alpha^{n-2}\right)+ q\) \(\left(\beta^{n-1}+\beta^{n-2}\right)\)
\(a_n=a_{n-1}+a_{ n -2}\)
\(\Rightarrow a_{12}=a_{11}+a_{10}\)
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