ExamBro
ExamBro
JEE Advanced · Mathematics · 9. Straight Lines

Paragraph:
A circle \(C\) of radius 1 is inscribed in an equilateral \(\triangle P Q R\). The points of contact of \(C\) with the sides \(P Q, Q R, R P\) are \(D, E, F\) respectively. The line \(P Q\) is given by the equation
\(\sqrt{3} x+y-6=0\) and the point \(D\) is \(\left(\frac{3 \sqrt{3}}{2}, \frac{3}{2}\right)\). Further, it is given that the origin and the centre of \(C\) are on the same side of the line \(P Q\).Question:
Equations of the sides \(Q R, R P\) are

  1. A
    \(y=\frac{2}{\sqrt{3}} x+1, y=-\frac{2}{\sqrt{3}} x-1\)
  2. B
    \(y=\frac{1}{\sqrt{3}} x, y=0\)
  3. C
    \(y=\frac{\sqrt{3}}{2} x+1, y=-\frac{\sqrt{3}}{2} x-1\)
  4. D
    \(y=\sqrt{3} x, y=0\)
Verified Solution

Answer & Solution

Correct Answer

(D)
\(y=\sqrt{3} x, y=0\)

Step-by-step Solution

Detailed explanation

Clearly, point \(E\) and \(F\) satisfy the equations given in option (d).
Same subject
Explore more questions on app
From JEE Advanced
Explore more questions on app