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JEE Advanced · Mathematics · 22. Functions

Let E1={x: x1 and xx-1>0} and E2={xE1: sin-1logexx-1 is a real number} (Here the inverse trigonometric function sin-1x assumes values in -π2. π2.)
Let f:E1 be the function defined by fx=logexx-1
And g:E2R be the function defined by gx=sin-1logexx-1 .
LIST-I LIST-II
A. The range of f is P. -,11-eee-1, 
B. The range of g contains Q. (0, 1)
C. The domain of f contains R. -12,12
D. The domain of g is S. -,00, 
  T. -,ee-1
  U. ( ,0 )( 1 2 , e e1 ]
The correct option is:

  1. A a-p;b-s;c-r;d-q;
  2. B a-u;b-p;c-t;d-r;
  3. C a-q;b-r;c-p;d-u;
  4. D a-s;b-q;c-p;d-p;
Verified Solution

Answer & Solution

Correct Answer

(D) a-s;b-q;c-p;d-p;

Step-by-step Solution

Detailed explanation

E1:xx-1>0

E1: x-,01,
E2:-1lnxx+11
1exx-1e
Now xx-1-1e0
e-1x+1ex-10

x ϵ -,11-e1,
Also xx-1-e0
e-1x-ex-10

x-,11-eee-1,
As Range of xx-1 is R+-1
Range of f is R-0 or -, 00,
Range of g is π2,π2 -0 or π2, 00,π2
Now P4, Q2, R1, S1
Hence A is correct.
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