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JEE Advanced · Mathematics · 21. ITF

For any positive integer n, define fn:0, R as fnx=i=1ntan-111+x+jx+j-1 for all x0, . (Here, the inverse trigonometric function tan-1x assumes values in -π2, π2) Then, which of the following statement(s) is (are) TRUE?

  1. A j=15tan2fj0=55
  2. B j=1101+fj'0sec2fj0=10
  3. C For any fixed positive integer n,limxtanfnx=1n
  4. D For any fixed positive integer nlimxsec2fnx=1
Verified Solution

Answer & Solution

Correct Answer

(D) For any fixed positive integer nlimxsec2fnx=1

Step-by-step Solution

Detailed explanation

fnx=j=1ntan-1x+j-x+j-11+x+jx+j-1 fnx=j=1ntan-1x+j-tan-1x+j-1
fnx=tan-1x+n-tan-1x
tanfnx=tantan-1x+n-tan-1x tanfnx=tantan-1x+n-x1+xx+n
tanfnx=n1+x2+nx, so that limxtanfnx=0
sec2fnx=1+tan2fnx
sec2fnx=1+n1+x2+nx2
limxsec2fnx=limx1+n1+x2+nx2=1
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