JEE Advanced · Mathematics · 5. Sequences & Series
Suppose four distinct positive numbers \(a_1, a_2, a_3\) and \(a_4\) are in GP. Let \(b_1=a_1\), \(b_2=b_1+a_2, b_3=b_2+a_3\) and \(b_4=b_3+a_4\).
Statement 1 The numbers \(b_1, b_2, b_3\) and \(b_4\) are neither in AP nor in GP.
Statement 2 The numbers \(b_1, b_2, b_3\) and \(b_4\) are in HP.
- A Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
- B Statement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 1.
- C Statement 1 is true, Statement 2 is false.
- D Statement 1 is false, Statement 2 is true
Answer & Solution
Correct Answer
(C) Statement 1 is true, Statement 2 is false.
Step-by-step Solution
Detailed explanation
Let \(a_1=1, a_2=2, a_3=4, a_4=8\)
\(\therefore b_1=1, b_2=3, b_3=7, b_4=15\)
Clearly, \(b_1, b_2, b_3\) and \(b_4\) are not in HP.
Statement 2 is false.
\(\therefore b_1=1, b_2=3, b_3=7, b_4=15\)
Clearly, \(b_1, b_2, b_3\) and \(b_4\) are not in HP.
Statement 2 is false.
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