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JEE Advanced · Mathematics · 14. Ellipse

Let \(P\left(x_1, y_1\right)\) and \(Q\left(x_2, y_2\right)\) be two distinct points on the ellipse
\(\frac{x^2}{9}+\frac{y^2}{4}=1\)
such that \(y_1>0\), and \(y_2>0\). Let C denote the circle \(x^2+y^2=9\), and \(M\) be the point \((3,0)\).
Suppose the line \(x=x_1\) intersects \(C\) at \(R\), and the line \(x=x_2\) intersects \(C\) at \(S\), such that the \(y\)-coordinates of \(R\) and \(S\) are positive. Let \(\angle R O M=\frac{\pi}{6}\) and \(\angle S O M=\frac{\pi}{3}\), where \(O\) denotes the origin \((0,0)\). Let \(|X Y|\) denote the length of the line segment \(X Y\).
Then which of the following statements is (are) TRUE?

  1. A The equation of the line joining \(P\) and \(Q\) is \(2 x+3 y=3(1+\sqrt{3})\)
  2. B The equation of the line joining \(P\) and \(Q\) is \(2 x+y=3(1+\sqrt{3})\)
  3. C If \(N_2=\left(x_2, 0\right)\), then \(3\left|N_2 Q\right|=2\left|N_2 S\right|\)
  4. D If \(N_1=\left(x_1, 0\right)\), then \(9\left|N_1 P\right|=4\left|N_1 R\right|\)
Verified Solution

Answer & Solution

Correct Answer

(C) If \(N_2=\left(x_2, 0\right)\), then \(3\left|N_2 Q\right|=2\left|N_2 S\right|\)

Step-by-step Solution

Detailed explanation


\(\begin{aligned} & \mathrm{P} \equiv\left(3 \cos 30^{\circ}, 2 \sin 30^{\circ}\right) \equiv\left(\frac{3 \sqrt{3}}{2}, 1\right) \\ & \mathrm{Q} \equiv\left(3 \cos 60^{\circ}, 2 \sin 60^{\circ}\right) \equiv\left(\frac{3}{2}, \sqrt{3}\right) \\ & \mathrm{R}\left(\frac{3 \sqrt{3}}{2}, \frac{3}{2}\right), \mathrm{S}\left(\frac{3}{2}, \frac{3 \sqrt{3}}{2}\right)\end{aligned}\)
Slope of \(\mathrm{PQ}=\mathrm{m}_{\mathrm{PQ}}=\frac{\sqrt{3}-1}{\frac{3}{2}-\frac{3 \sqrt{3}}{2}}=-\frac{2}{3}\)
Equation of line PQ
\(\mathrm{y}-\sqrt{3}=-\frac{2}{3}\left(\mathrm{x}-\frac{3}{2}\right)\)
\(\Rightarrow 2 x+3 y=3(\sqrt{3}+1) \quad\) option (A) is correct
Now
\(\begin{aligned} & \text { if } \mathrm{N}_2=\left(\mathrm{x}_2, 0\right)=\left(\frac{3}{2}, 0\right) \\ & \left|\mathrm{N}_2 \mathrm{Q}\right|=\sqrt{3} \text { and }\left|\mathrm{N}_2 \mathrm{~S}\right|=\frac{3 \sqrt{3}}{2}\end{aligned}\)
\(\Rightarrow 3\left|\mathrm{~N}_2 \mathrm{Q}\right|=2\left|\mathrm{~N}_2 \mathrm{~S}\right| \quad\) option (C) is correct
Now, if \(\mathrm{N}_1=\left(\mathrm{x}_1, 0\right) \Rightarrow \mathrm{N}_1=\left(\frac{3 \sqrt{3}}{2}, 0\right)\)
\(\Rightarrow\left|\mathrm{N}_1 \mathrm{P}\right|=1,\left|\mathrm{~N}_1 \mathrm{R}\right|=\frac{3}{2} \quad\) option (D) is incorrect
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