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JEE Advanced · Chemistry · 25. Alcohols, Phenols & Ethers

When benzene sulphonic acid and \(p\)-nitrophenol are treated with \(\mathrm{NaHCO}_3\), the gases released respectively are

  1. A \(\mathrm{SO}_2, \mathrm{NO}_2\)
  2. B \(\mathrm{SO}_2, \mathrm{NO}\)
  3. C \(\mathrm{SO}_2, \mathrm{CO}_2\)
  4. D \(\mathrm{CO}_2, \mathrm{CO}_2\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\mathrm{CO}_2, \mathrm{CO}_2\)

Step-by-step Solution

Detailed explanation

Benzene sulphonic acid and p-nitrophenol react with \(\text{NaHCO} _3\) and evolve \(\text{CO} _2\) gas.

Because benezene sulphonic acid and \(p\)-nitro phenol are stronger acids with \(\mathrm{H}_2 \mathrm{CO}_3\) (i.e., \(\mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2\) ) so, they are capable to evolve \(\mathrm{CO}_2\) with \(\mathrm{NaHCO}_3\).
\(\mathrm{HCO}_3^{-}+\underset{\text { Acid }}{\mathrm{H}^{+}} \rightarrow \mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2 \uparrow\)
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