JEE Advanced · Chemistry · 17. Electrochemistry
For the reduction of \(\mathrm{NO}_3^{-}\)ion in an aqueous solution \(E^{\circ}\) is \(+0.96 \mathrm{~V}\). Values of \(E^{\circ}\) for some metal ions are given below.
\(
\begin{aligned}
& \mathrm{V}^{2+}(a q)+2 e^{-} \longrightarrow \mathrm{V} ; E^{\circ}=-1.19 \mathrm{~V} \\
& \mathrm{Fe}^{3+}(a q)+3 e^{-} \longrightarrow \mathrm{Fe} ; \mathrm{E}^{\circ}=-0.04 \mathrm{~V} \\
& \mathrm{Au}^{3+}(a q)+3 e^{-} \longrightarrow \mathrm{Au} ; E^{\circ}=+1.40 \mathrm{~V}
\end{aligned}
\)
\(
\mathrm{Hg}^{2+}(a q)+2 e^{-} \longrightarrow \mathrm{Hg} ; E^{\circ}=+0.86 \mathrm{~V}
\)
The pair(s) of metals that is (are) oxidised by \(\mathrm{NO}_3^{-}\)in aqueous solution is (are)
- A \(\mathrm{V}\) and \(\mathrm{Hg}\)
- B \(\mathrm{Hg}\) and \(\mathrm{Fe}\)
- C Fe and Au
- D \(\mathrm{Fe}\) and \(\mathrm{V}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{V}\) and \(\mathrm{Hg}\)
Step-by-step Solution
Detailed explanation
The species having less reduction potential with respect to \(\mathrm{NO}_3^{-}\left(E^{\circ}=0.96 \mathrm{~V}\right)\) will be oxidised by \(\mathrm{NO}_3^{-}\); These species are \(\mathrm{V}, \mathrm{Fe}, \mathrm{Hg}\).
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