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JEE Advanced · Physics · 4. Motion in 2D

A particle of mass m is projected from the ground with an initial speed u at an angle α with the horizontal. At the highest point of its trajectory, it makes a completely inelastic collision with another identical particle, which was thrown vertically upward from the ground with the same initial speed u. The angle that the composite system makes with the horizontal immediately after the collision is

  1. A π 4
  2. B π 2 + α
  3. C π 2 - α
  4. D π 2
Verified Solution

Answer & Solution

Correct Answer

(A) π 4

Step-by-step Solution

Detailed explanation

At the highest point

\(v_{1}=\frac{u_{0} \cos \alpha}{2} \quad\) (by applying momentum conservation in horizontal direction)
\(\mathrm{v}_{2}=\frac{\mathrm{u}_{0} \cos \alpha}{2} \quad\) (by applying momentum conservation in vertical direction)
\(\theta=45^{\circ}\left(\mathrm{H}=\frac{\mathrm{u}_{0}^{2} \sin ^{2} \alpha}{2 \mathrm{~g}}\right)\)
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