JEE Advanced · Chemistry · 14. Hydrocarbons
The option(s) with correct sequence of reagents for the conversion of \(\mathbf{P}\) to \(\mathbf{Q}\) is(are) :

- A i) Lindlar's catalyst, \(\mathrm{H}_2\); ii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iii) \(\mathrm{NaBH}_4\); iv) \(\mathrm{H}_3 \mathrm{O}^{+}\)
- B i) Lindlar's catalyst, \(\mathrm{H}_2\); ii) \(\mathrm{H}_3 \mathrm{O}^{+}\); iii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iv) \(\mathrm{NaBH}_4\)
- C i) \(\mathrm{NaBH}_4\); ii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iii) \(\mathrm{H}_3 \mathrm{O}^{+}\); iv) Lindlar's catalyst, \(\mathrm{H}_2\)
- D i) Lindlar's catalyst, \(\mathrm{H}_2\); ii) \(\mathrm{NaBH}_4\); iii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iv) \(\mathrm{H}_3 \mathrm{O}^{+}\)
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Correct Answer
(D) i) Lindlar's catalyst, \(\mathrm{H}_2\); ii) \(\mathrm{NaBH}_4\); iii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iv) \(\mathrm{H}_3 \mathrm{O}^{+}\)
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