ExamBro
ExamBro
JEE Advanced · Chemistry · 14. Hydrocarbons

The option(s) with correct sequence of reagents for the conversion of \(\mathbf{P}\) to \(\mathbf{Q}\) is(are) :

  1. A i) Lindlar's catalyst, \(\mathrm{H}_2\); ii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iii) \(\mathrm{NaBH}_4\); iv) \(\mathrm{H}_3 \mathrm{O}^{+}\)
  2. B i) Lindlar's catalyst, \(\mathrm{H}_2\); ii) \(\mathrm{H}_3 \mathrm{O}^{+}\); iii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iv) \(\mathrm{NaBH}_4\)
  3. C i) \(\mathrm{NaBH}_4\); ii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iii) \(\mathrm{H}_3 \mathrm{O}^{+}\); iv) Lindlar's catalyst, \(\mathrm{H}_2\)
  4. D i) Lindlar's catalyst, \(\mathrm{H}_2\); ii) \(\mathrm{NaBH}_4\); iii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iv) \(\mathrm{H}_3 \mathrm{O}^{+}\)
Verified Solution

Answer & Solution

Correct Answer

(D) i) Lindlar's catalyst, \(\mathrm{H}_2\); ii) \(\mathrm{NaBH}_4\); iii) \(\mathrm{SnCl}_2 / \mathrm{HCl}\); iv) \(\mathrm{H}_3 \mathrm{O}^{+}\)

Step-by-step Solution

Detailed explanation

Same subject
Explore more questions on app