JEE Advanced · Chemistry · 22. d & f Block
Reduction of the metal centre in aqueous permanganate ion involves
- A three electrons in neutral medium
- B five electrons in neutral medium
- C three electrons in alkaline medium
- D five electrons in acidic medium
Answer & Solution
Correct Answer
(A) three electrons in neutral medium
Step-by-step Solution
Detailed explanation
In neutral medium: \(\quad \mathrm{MnO}_4^{-} \rightarrow \mathrm{MnO}_2\left(\mathrm{Mn}^{7+}+3 e^{-} \rightarrow \mathrm{Mn}^{4+}\right)\)
In alkaline medium : \(\quad \mathrm{MnO}_4^{-} \rightarrow \mathrm{MnO}_2\left(\mathrm{Mn}^{7+}+3 \varepsilon^{-} \rightarrow \mathrm{Mn}^{4+}\right)\)
In acidic medium : \(\quad \mathrm{Mn}_4^{-} \rightarrow \mathrm{Mn}^{2+}\left(\mathrm{Mn}^{7+}+5 e^{-} \rightarrow \mathrm{Mn}^{2+}\right)\)
In alkaline medium : \(\quad \mathrm{MnO}_4^{-} \rightarrow \mathrm{MnO}_2\left(\mathrm{Mn}^{7+}+3 \varepsilon^{-} \rightarrow \mathrm{Mn}^{4+}\right)\)
In acidic medium : \(\quad \mathrm{Mn}_4^{-} \rightarrow \mathrm{Mn}^{2+}\left(\mathrm{Mn}^{7+}+5 e^{-} \rightarrow \mathrm{Mn}^{2+}\right)\)
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