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JEE Advanced · Chemistry · 22. d & f Block

Reduction of the metal centre in aqueous permanganate ion involves

  1. A three electrons in neutral medium
  2. B five electrons in neutral medium
  3. C three electrons in alkaline medium
  4. D five electrons in acidic medium
Verified Solution

Answer & Solution

Correct Answer

(A) three electrons in neutral medium

Step-by-step Solution

Detailed explanation

In neutral medium: \(\quad \mathrm{MnO}_4^{-} \rightarrow \mathrm{MnO}_2\left(\mathrm{Mn}^{7+}+3 e^{-} \rightarrow \mathrm{Mn}^{4+}\right)\)
In alkaline medium : \(\quad \mathrm{MnO}_4^{-} \rightarrow \mathrm{MnO}_2\left(\mathrm{Mn}^{7+}+3 \varepsilon^{-} \rightarrow \mathrm{Mn}^{4+}\right)\)
In acidic medium : \(\quad \mathrm{Mn}_4^{-} \rightarrow \mathrm{Mn}^{2+}\left(\mathrm{Mn}^{7+}+5 e^{-} \rightarrow \mathrm{Mn}^{2+}\right)\)
From JEE Advanced
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