JEE Advanced · Chemistry · 6. Thermodynamics (C)
A monoatomic ideal gas undergoes a process in which the ratio of \(P\) to \(V\) at any instant is constant and equals to 1 . What is the molar heat capacity of the gas?
- A \(\frac{4 R}{2}\)
- B \(\frac{3 R}{2}\)
- C \(\frac{5 R}{2}\)
- D \(0\)
Answer & Solution
Correct Answer
(A) \(\frac{4 R}{2}\)
Step-by-step Solution
Detailed explanation
The molar heat capacity for any process is given by a following expression
\(C=C_V+\frac{R}{1-\gamma}\) when \(p V^\gamma=\) constant and \(C_p / C_V=\gamma\)
Here, \(\frac{p}{V}=1\) i.e., \(p V^{-1}=\) constant
\(
\therefore C=\frac{3}{2} R+\frac{R}{1-(-1)}=\frac{3}{2} R+\frac{R}{2}=\frac{4}{2} R
\)
\(C=C_V+\frac{R}{1-\gamma}\) when \(p V^\gamma=\) constant and \(C_p / C_V=\gamma\)
Here, \(\frac{p}{V}=1\) i.e., \(p V^{-1}=\) constant
\(
\therefore C=\frac{3}{2} R+\frac{R}{1-(-1)}=\frac{3}{2} R+\frac{R}{2}=\frac{4}{2} R
\)
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