JEE Advanced · Chemistry · 23. Coordination Compounds
Paragraph:
The coordination number of \(\mathrm{Ni}^{2+}\) is 4 .
\(\mathrm{NiCl}_2+\mathrm{KCN}\) (excess) \(\rightarrow A\) (cyano complex)
\(\mathrm{NiCl}_2+\) conc. \(\mathrm{HCl}\) (excess) \(\rightarrow B\) (chloro complex)
Question:
The hybridization of \(A\) and \(B\) are
- A \(d s p^2, s p^3\)
- B \(s p^3, s p^3\)
- C \(d s p^2, d s p^2\)
- D \(s p^3 d^2, d^2 s p^3\)
Answer & Solution
Correct Answer
(A) \(d s p^2, s p^3\)
Step-by-step Solution
Detailed explanation
Hybridisation of \(\mathrm{Ni}\) in \(\mathrm{K}_2\left[\mathrm{Ni}(\mathrm{CN})_4\right]\) is \(d s p^2\) and in \(\mathrm{K}_2\left[\mathrm{Ni}^2\left(\mathrm{Cl}_4\right)\right]\) is \(s p^3\) (Detail see in question no. 25).
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