JEE Advanced · Chemistry · 6. Thermodynamics (C)
For the process \(\mathrm{H}_2 \mathrm{O}(\mathrm{l})\) (1 bar, \(\left.273 \mathrm{~K}\right) \longrightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})\) (1 bar, \(\left.373 \mathrm{~K}\right)\), the correct set of thermodynamic parameters is
- A \(\Delta G=0, \Delta S=+\) ve
- B \(\Delta G=0, \Delta S=-v e\)
- C \(\Delta G=+v e, \Delta S=0\)
- D \(\Delta G=-v e, \Delta S=+v e\)
Answer & Solution
Correct Answer
(A) \(\Delta G=0, \Delta S=+\) ve
Step-by-step Solution
Detailed explanation
\(\mathrm{H}_2 \mathrm{O}(l)\) and \(\mathrm{H}_2 \mathrm{O}(g)\) both exist together at same temperature and pressure, suggests the state of equilibrium
Hence, \(\quad \Delta G=0\) and conversion of liquid into gas increases disorderness, entropy hence \(\Delta S=+v e\).
Hence, \(\quad \Delta G=0\) and conversion of liquid into gas increases disorderness, entropy hence \(\Delta S=+v e\).
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