JEE Advanced · Chemistry · 24. Haloalkanes & Haloarenes
Match the reactions in List-I with the features of their products in List-II and choose the correct option.
| List - I | List - II |
(P) ![]() | 1. Inversion of configuration |
(Q) ![]() | 2. Retention of configuration |
(R) ![]() | 3. Mixture of enantiomers |
(S) ![]() | 4. Mixture of structural isomers |
| 5. Mixture of diastereomers |
- A
- B
- C
- D
Answer & Solution
Correct Answer
(B)
Step-by-step Solution
Detailed explanation
\(1-\underset{\text { (Single enantiomer) }}{\text { Bromo }-2-\text { ethylpentane }} \xrightarrow[\text S _{\text N } 2 \text { reaction }]{\text { aq. } \text{NaOH} }\) \(2-\text{ethylpentanol}\) In the above reaction the chiral carbon is not involving in the reaction as reaction takes place via formation of transition state but not through formation of intermediate.
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Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator automobiles.
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