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JEE Advanced · Chemistry · 24. Haloalkanes & Haloarenes

Match the reactions in List-I with the features of their products in List-II and choose the correct option.
List - IList - II
(P)
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1. Inversion of configuration
(Q)
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2. Retention of configuration
(R)
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3. Mixture of enantiomers
(S)
4. Mixture of structural isomers
5. Mixture of diastereomers

  1. A P  1; Q  2; R  5; S  3
  2. B P  2; Q  1; R  3; S  5
  3. C P1; Q2; R5; S4
  4. D P  2; Q  4; R  3; S  5
Verified Solution

Answer & Solution

Correct Answer

(B) P  2; Q  1; R  3; S  5

Step-by-step Solution

Detailed explanation

\(1-\underset{\text { (Single enantiomer) }}{\text { Bromo }-2-\text { ethylpentane }} \xrightarrow[\text S _{\text N } 2 \text { reaction }]{\text { aq. } \text{NaOH} }\) \(2-\text{ethylpentanol}\) In the above reaction the chiral carbon is not involving in the reaction as SN2 reaction takes place via formation of transition state but not through formation of intermediate.
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