JEE Advanced · Chemistry · 4. Chemical Bonding
If the bond length of \(\mathrm{CO}\) bond in carbon monoxide is \(1.128 \mathrm{~A}^{\circ}\), then what is the value of \(\mathrm{CO}\) bond length in \(\mathrm{Fe}(\mathrm{CO})_5\) ?
- A \(1.15 Å\)
- B \(1.128 Å\)
- C \(1.72 Å\)
- D \(1.118 Å\)
Answer & Solution
Correct Answer
(A) \(1.15 Å\)
Step-by-step Solution
Detailed explanation
The metal (Fe) makes the back bonding to \(\mathrm{CO}\). The metal to ligand bonding creates a synergic effect which strengthens the bond \(\mathrm{CO}\) and the metal ( \(\mathrm{Fe}\) ). Which results in the contraction of \(\mathrm{CO}\) bond length (Synergic means working together towards a common end. This is a bond formed by a ligand to metal ion which has a \(\sigma\)-bond from ligand to metal ion and the back donation of electron density from the metal to the \(\pi^*\) orbitals on the ligand. Thus enhancing the acceptor strength of the p-orbital. Hence up to a point the effect of \(\sigma\)-bond formation strengthens the \(\pi\)-bonding or vice-versa. Due to this synergic effect bond order decreases.
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