JEE Advanced · Chemistry · 6. Thermodynamics (C)
The direct conversion of \(A\) to \(B\) is difficult, hence it is carried out by the following shown path.

Given \(\Delta S_{(A \rightarrow C)}=50 \mathrm{eu}, \quad \Delta S_{(C \rightarrow D)}=30 \mathrm{eu}, \quad\) \(\Delta S_{(B \rightarrow D)}=20 \mathrm{eu}\) where eu is entropy unit, then \(\Delta S_{(A \rightarrow B)}\) is
- A \(+100 \mathrm{eu}\)
- B \(+60 \mathrm{eu}\)
- C \(-100 \mathrm{eu}\)
- D \(-60\) eu
Answer & Solution
Correct Answer
(B) \(+60 \mathrm{eu}\)
Step-by-step Solution
Detailed explanation

Given: \(\Delta S_{(A \rightarrow C)}=50 \mathrm{eu}, \Delta S_{(C \rightarrow D)}=30 \mathrm{eu}, \Delta S_{(B \rightarrow D)}\)\(=20 \mathrm{eu}\) where eu is entropy unit.
\( \text {Therefore, }\Delta S_{(A \rightarrow B)} =\Delta S_{(A \rightarrow C)}+\Delta S_{(C \rightarrow D)}+\)\(\Delta S_{(D \rightarrow B)} \)
\( =\Delta S_{(A \rightarrow C)}+\Delta S_{(C \rightarrow D)}-\Delta S_{(B \rightarrow D)} \)
\( =50+30-20=60 \mathrm{eu}\)
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