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JEE Advanced · Chemistry · 8. Ionic Equilibrium

For the following reaction, the equilibrium constant Ke at 298 K is 1.6×1017.
Fe2+aq+S2-aq FeSs
When equal volumes of 0.06 M Fe2+aq and 0.2 M S2-aq solutions are mixed, the equilibrium concentration of Fe2+aq is found to be Y×10-17M. The value of Y is __________

  1. A 8.93
  2. B 95.45
  3. C 5.465
  4. D 2.63
Verified Solution

Answer & Solution

Correct Answer

(A) 8.93

Step-by-step Solution

Detailed explanation

Fe2++S2-Fe S(s) ..... Kc=1.6×1017
t=0 : 0.03 M 0.1 M
t=t; 0.03-H 0.1 H
Since Kc>>1,
n0.03
[S2-]=0.1-0.031=0.07 M
Kc=Fe2+S2-=11.6×1017
Fe2+=11.6×0.07×10-17
y=11.6×0.078.93
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