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JEE Advanced · Chemistry · 25. Alcohols, Phenols & Ethers

A trinitro compound, 1,3,5-tris-(4-nitrophenyl) benzene, on complete reaction with an excess of Sn/HCl gives a major product, which on treatment with an excess of NaNO2/HCl at 0°C provides P as the product. P, upon treatment with excess of H2O at room temperature, gives the product Q. Bromination of Q in aqueous medium furnishes the product R. The compound P upon treatment with an excess of phenol under basic conditions gives the product S. The molar mass difference between compounds Q and R is 474 g mol-1 and between compounds P and S is 172.5 g mol-1.
The total number of carbon atoms and heteroatoms present in one molecule of \(S\) is
[Use: Molar mass (in \(\text{gmol} ^{-1}\) ): \(\text H =1,\text C =12,\text N=14,\text O =16,\) \(\text{Br} =80, \text{Cl} =35.5\) Atoms other than C and H are considered as heteroatoms]

  1. A 50
  2. B 51
  3. C 52
  4. D 53
Verified Solution

Answer & Solution

Correct Answer

(B) 51

Step-by-step Solution

Detailed explanation

Nitrobenzene part converts to aniline part using Sn/HCl. Aniline forms diazonium salt with nitrous acid and hydrogen chloride. Diazonium salt forms phenol with warm water.Phenol forms poly substituted bromo compound with bromine water.


The compound P, on reaction with phenol gives coupling reaction and gives a coloured dye.

Total number of carbon atoms in S are 42 and hetero atoms are 9(Nitrogen and oxygen).
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