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GUJCET · Physics · Electric Charges and Fields
Two large, thin metal plates are parallel and close to each other on their inner faces, the plates have surface charge densities of same signs and of magnitude \(17.7 \times 10^{-22} C / m ^2\). What is E in the outer region of the second plate?
- A \(2 \times 10^{-10} NC ^{-1}\)
- B \(1 \times 10^{-10} NC ^{-1}\)
- C \(4 \times 10^{-10} NC ^{-1}\)
- D Zero
Answer & Solution
Correct Answer
(A) \(2 \times 10^{-10} NC ^{-1}\)
Step-by-step Solution
Detailed explanation
(A)
Total electric field at outer region of second plate
\(\begin{array}{l}
E=E_1+E_2 \\
E=\frac{\sigma}{2 \varepsilon_0}+\frac{\sigma}{2 \varepsilon_0}\left(\because \sigma_1=\sigma_1=\sigma\right) \\
E=\frac{\sigma}{\varepsilon_0} \\
E=\frac{17.7 \times 10^{-22}}{8.85 \times 10^{-10}} \\
E=2 \times 10^{-10} NC^{-1}
\end{array}
\)
Total electric field at outer region of second plate
\(\begin{array}{l}
E=E_1+E_2 \\
E=\frac{\sigma}{2 \varepsilon_0}+\frac{\sigma}{2 \varepsilon_0}\left(\because \sigma_1=\sigma_1=\sigma\right) \\
E=\frac{\sigma}{\varepsilon_0} \\
E=\frac{17.7 \times 10^{-22}}{8.85 \times 10^{-10}} \\
E=2 \times 10^{-10} NC^{-1}
\end{array}
\)
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