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GUJCET · Physics · Nuclei
In the given nuclear reaction \({ }_{4}^{9} \mathrm{Be}+{ }_{2}^{4} \mathrm{He} \rightarrow{ }_{6}^{12} \mathrm{C}+\mathrm{X}\) X represents \(\qquad\)
- A \(e\) (electron)
- B \(p\) (proton)
- C \(n\) (neutron)
- D \(v\) (neutrino)
Answer & Solution
Correct Answer
(C) \(n\) (neutron)
Step-by-step Solution
Detailed explanation
C.\(n\) (neutron)
\({ }_{4}^{9} \mathrm{Be}+{ }_{2}^{4} \mathrm{He} \rightarrow{ }_{6}^{12} \mathrm{C}+{ }_{0}^{1} n\)
\({ }_{4}^{9} \mathrm{Be}+{ }_{2}^{4} \mathrm{He} \rightarrow{ }_{6}^{12} \mathrm{C}+{ }_{0}^{1} n\)
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