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GUJCET · Physics · Electromagnetic Induction
A conducting ring of radius \(r\) is placed perpendicularly inside a time varying magnetic field given by \(B = B _0+\alpha t\) as shown in fig. \(B _0\) and \(\alpha\) are positive constants. Find \(e m f\) produced in the ring.

- A \(-\pi \alpha^2 r^2\)
- B \(-\pi \alpha^2 r\)
- C \(-\pi \alpha r^2\)
- D \(-\pi \alpha r\)
Answer & Solution
Correct Answer
(C) \(-\pi \alpha r^2\)
Step-by-step Solution
Detailed explanation
C
\(\begin{array}{l}\varepsilon=-\frac{d \phi}{d t} \\ \varepsilon=-\frac{d}{d t}( AB ) \\ \varepsilon=-\frac{d}{d t}\left[\pi r^2 \times\left( B _0+\alpha t\right)\right] \\ \varepsilon=-\pi r^2 \frac{d}{d t}\left(B_0+\alpha t\right) \\ \varepsilon=-\pi r^2 \alpha\end{array}\)
\(\begin{array}{l}\varepsilon=-\frac{d \phi}{d t} \\ \varepsilon=-\frac{d}{d t}( AB ) \\ \varepsilon=-\frac{d}{d t}\left[\pi r^2 \times\left( B _0+\alpha t\right)\right] \\ \varepsilon=-\pi r^2 \frac{d}{d t}\left(B_0+\alpha t\right) \\ \varepsilon=-\pi r^2 \alpha\end{array}\)
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