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GUJCET · Physics · Dual Nature of Radiation and Matter
The threshold frequency of cesium is \(5.16 \times 10^{14}\) Hz. Then its work function is _________ \(e \mathrm{~V}\).
- A 4.12
- B 2.14
- C 1.12
- D 1.14
Answer & Solution
Correct Answer
(B) 2.14
Step-by-step Solution
Detailed explanation
(B) 2.14
work function,
\(\phi_{0}=h v_{0}\)
\(\phi_{0}=\frac{6.625 \times 10^{-34} \times 5.16 \times 10^{14}}{1.6 \times 10^{-19}}\)
\(\phi_{0}=2.136 \mathrm{eV}\)
\(\phi_{0} \approx 2.14 \mathrm{eV}\)
work function,
\(\phi_{0}=h v_{0}\)
\(\phi_{0}=\frac{6.625 \times 10^{-34} \times 5.16 \times 10^{14}}{1.6 \times 10^{-19}}\)
\(\phi_{0}=2.136 \mathrm{eV}\)
\(\phi_{0} \approx 2.14 \mathrm{eV}\)
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