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GUJCET · Maths · Vector Algebra

If \(\vec{a}=2 \hat{i}-\hat{j}+\hat{k}, \vec{b}=\hat{i}+\hat{j}-2 \hat{k}\), \(\vec{c}=\hat{i}+3 \hat{j}-\hat{k}\) are given vectors. If \(\vec{a}\) is perpendicular to \(\lambda \vec{b}+\vec{c}\) then \(\lambda=\) _________ .

  1. A -2
  2. B \(0\)
  3. C 2
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(A) -2

Step-by-step Solution

Detailed explanation

\(\vec{a} \cdot (\lambda \vec{b}+\vec{c}) = 0\) \((2 \hat{i}-\hat{j}+\hat{k}) \cdot ((\lambda+1)\hat{i} + (\lambda+3)\hat{j} + (-2\lambda-1)\hat{k}) = 0\)