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GUJCET · Maths · Vector Algebra
If \(\vec{a}=2 \hat{i}-\hat{j}+\hat{k}, \vec{b}=\hat{i}+\hat{j}-2 \hat{k}\), \(\vec{c}=\hat{i}+3 \hat{j}-\hat{k}\) are given vectors. If \(\vec{a}\) is perpendicular to \(\lambda \vec{b}+\vec{c}\) then \(\lambda=\) _________ .
- A -2
- B \(0\)
- C 2
- D 3
Answer & Solution
Correct Answer
(A) -2
Step-by-step Solution
Detailed explanation
\(\vec{a} \cdot (\lambda \vec{b}+\vec{c}) = 0\) \((2 \hat{i}-\hat{j}+\hat{k}) \cdot ((\lambda+1)\hat{i} + (\lambda+3)\hat{j} + (-2\lambda-1)\hat{k}) = 0\)
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