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GUJCET · Physics · Moving Charges and Magnetism
The horizontal component of the Earth's magnetic field at a certain plate is \(3 \times 10^{-5} T\) and the direction of the field is from the geographic South to the geographic North. A very long straight conductor is carrying a steady current of 1 A . What is the force per unit length on it when it is placed on a horizontal table and the direction of current is South to North?
- A Zero
- B \(6 \times 10^{-5} Nm ^{-1}\)
- C \(1 \times 10^{-5} Nm ^{-1}\)
- D \(9 \times 10^{-5} Nm ^{-1}\)
Answer & Solution
Correct Answer
(A) Zero
Step-by-step Solution
Detailed explanation
\( \frac{F}{L} = BI \sin\theta \) \( \theta = 0^{\circ} \) (current and field are parallel)
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