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GUJCET · Physics · Magnetism And Matter
At certain place on the surface of the earth, horizontal component of earth's magnetic field is same as vertical component of earth magnetic field, then what will be angle of dip at that place ?
- A \(60^{\circ}\)
- B \(45^{\circ}\)
- C \(30^{\circ}\)
- D \(90^{\circ}\)
Answer & Solution
Correct Answer
(B) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
B
\(\begin{array}{l}\tan I =\frac{ Z _{ E }}{ H _{ E }} \\ \tan I =\frac{ Z _{ E }}{ Z _{ E }} \quad\left(\because Z _{ E }= H _{ E }\right)\end{array}\)
\(\begin{aligned} \therefore \quad \tan I =1 \\ I =\tan ^{-1} 1=45^{\circ}\end{aligned}\)
\(\begin{array}{l}\tan I =\frac{ Z _{ E }}{ H _{ E }} \\ \tan I =\frac{ Z _{ E }}{ Z _{ E }} \quad\left(\because Z _{ E }= H _{ E }\right)\end{array}\)
\(\begin{aligned} \therefore \quad \tan I =1 \\ I =\tan ^{-1} 1=45^{\circ}\end{aligned}\)
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