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GUJCET · Physics · Electromagnetic Waves
The sun delivers \(10^{3} \mathbf{W m}^{-2}\) of Electromagnetic flux on the Earth's surface. The total power that is incident on a roof of dimensions \(6 \mathrm{~m} \times 30 \mathrm{~m}\) is __________ .
- A \(7.2 \times 10^{5} \mathrm{~W}\)
- B \(4.5 \times 10^{5} \mathrm{~W}\)
- C \(1.8 \times 10^{5} \mathrm{~W}\)
- D \(0.9 \times 10^{5} \mathrm{~W}\)
Answer & Solution
Correct Answer
(C) \(1.8 \times 10^{5} \mathrm{~W}\)
Step-by-step Solution
Detailed explanation
(C) \(1.8 \times 10^{5} \mathrm{~W}\)
\(\quad\) intensity of radiation \(I=\frac{P}{A}\)
\(
\text { power } \begin{aligned}
\mathrm{P} & =\mathrm{IA} \\
\mathrm{P} & =10^{3} \times 6 \times 30 \\
\mathrm{P} & =180 \times 10^{3} \\
\mathrm{P} & =1.8 \times 10^{5} \mathrm{~W}
\end{aligned}
\)
intensity of radiation
\(
\begin{aligned}
& =\frac{\text { energy }}{\text { time } \times \text { area }} \\
I & =\frac{M^{1} L^{2} T^{-2}}{T^{1} \times L^{2}} \\
I & =M^{1} L^{0} T^{-3}
\end{aligned}
\)
\(\quad\) intensity of radiation \(I=\frac{P}{A}\)
\(
\text { power } \begin{aligned}
\mathrm{P} & =\mathrm{IA} \\
\mathrm{P} & =10^{3} \times 6 \times 30 \\
\mathrm{P} & =180 \times 10^{3} \\
\mathrm{P} & =1.8 \times 10^{5} \mathrm{~W}
\end{aligned}
\)
intensity of radiation
\(
\begin{aligned}
& =\frac{\text { energy }}{\text { time } \times \text { area }} \\
I & =\frac{M^{1} L^{2} T^{-2}}{T^{1} \times L^{2}} \\
I & =M^{1} L^{0} T^{-3}
\end{aligned}
\)
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