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GUJCET · Physics · Current Electricity
Two wires of equal length and equal diameter and having resistivities \(\rho_1\) and \(\rho_2\) are connected in series. The equivalent resistivity of the combination is _________.
- A \(\rho_1+\rho_2\)
- B \(\frac{\rho_1+\rho_2}{2}\)
- C \(\frac{\rho_1 \rho_2}{\rho_1+\rho_2}\)
- D \(\sqrt{\rho_1 \rho_2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\rho_1+\rho_2}{2}\)
Step-by-step Solution
Detailed explanation
(B)

\(R=R_1+R_2\)
\(\frac{\rho(2 l)}{ A }=\frac{\rho_1 l}{A}+\frac{\rho_2 l}{A}\)
\(\begin{array}{ll}\therefore & 2 \rho=\rho_1+\rho_2 \\ \therefore & \rho=\frac{\rho_1+\rho_2}{2}\end{array}\)

\(R=R_1+R_2\)
\(\frac{\rho(2 l)}{ A }=\frac{\rho_1 l}{A}+\frac{\rho_2 l}{A}\)
\(\begin{array}{ll}\therefore & 2 \rho=\rho_1+\rho_2 \\ \therefore & \rho=\frac{\rho_1+\rho_2}{2}\end{array}\)
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