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GUJCET · Physics · Alternating Current
In L-C-R AC series circuit \(\mathrm{L}=9 \mathrm{H}\), \(R=10 \Omega \& C=100 \mu F\). Hence \(Q\) factor of the circuit is ____________.
- A 35
- B 25
- C 45
- D 30
Answer & Solution
Correct Answer
(D) 30
Step-by-step Solution
Detailed explanation
(D) 30
\(Q=\frac{1}{R} \sqrt{\frac{L}{C}}\)
\(Q=\frac{1}{10} \sqrt{\frac{9}{100 \times 10^{-6}}}\)
\(\mathrm{Q}=\frac{3}{10 \times 10^{-2}}=30\)
\(Q=\frac{1}{R} \sqrt{\frac{L}{C}}\)
\(Q=\frac{1}{10} \sqrt{\frac{9}{100 \times 10^{-6}}}\)
\(\mathrm{Q}=\frac{3}{10 \times 10^{-2}}=30\)
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