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GUJCET · Physics · Electromagnetic Waves
A plane electromagnetic wave of frequency \(\mathbf{2 5 ~ M H z}\) travels in free space along the X-direction. At a particular point in space and time, where \(\overrightarrow{\mathrm{B}}=2.1 \times 10^{-8} \hat{k}\) T. Then find \(\overrightarrow{\mathrm{E}}\) at this point.
- A \(-2.1 \hat{j} \mathrm{Vm}^{-1}\)
- B \(6.3 \hat{j} \mathrm{Vm}^{-1}\)
- C \(4.2 \hat{j} \mathrm{Vm}^{-1}\)
- D \(-3.2 \hat{j} \mathrm{Vm}^{-1}\)
Answer & Solution
Correct Answer
(B) \(6.3 \hat{j} \mathrm{Vm}^{-1}\)
Step-by-step Solution
Detailed explanation
(B) \(6.3 \hat{j} \mathrm{Vm}^{-1}\)
\(\frac{\mathrm{E}}{\mathrm{B}}=c\)
\(\mathrm{E}=c \mathrm{~B}\)
\(\mathrm{E}=3 \times 10^{8} \times 2.1 \times 10^{-8}\)
\(\mathrm{E}=6.3 \mathrm{Vm}^{-1}\)
direction of \(\vec{E} \times \vec{B}=\) direction of \(c\)
\(
\begin{aligned}
\overrightarrow{\mathrm{E}} \times \hat{k} & =\hat{i} \\
\text { direction of } \overrightarrow{\mathrm{E}} & =\hat{j}
\end{aligned}
\)
\(\therefore \overrightarrow{\mathrm{E}}=6.3 \hat{j} \mathrm{Vm}^{-1}\)
\(\frac{\mathrm{E}}{\mathrm{B}}=c\)
\(\mathrm{E}=c \mathrm{~B}\)
\(\mathrm{E}=3 \times 10^{8} \times 2.1 \times 10^{-8}\)
\(\mathrm{E}=6.3 \mathrm{Vm}^{-1}\)
direction of \(\vec{E} \times \vec{B}=\) direction of \(c\)
\(
\begin{aligned}
\overrightarrow{\mathrm{E}} \times \hat{k} & =\hat{i} \\
\text { direction of } \overrightarrow{\mathrm{E}} & =\hat{j}
\end{aligned}
\)
\(\therefore \overrightarrow{\mathrm{E}}=6.3 \hat{j} \mathrm{Vm}^{-1}\)
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