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GUJCET · Physics · Nuclei
Find the value of \(x\) and \(y\) in the following nuclear reaction.
\({ }_{92}^{235} \mathrm{U}+{ }_0^1 n \rightarrow{ }_x^{133} \mathrm{Sb}+{ }_{41}^y \mathrm{Nb}+4{ }_0^1 n\)
- A \((51,95)\)
- B \((51,99)\)
- C \((92,1)\)
- D \((133,41)\)
Answer & Solution
Correct Answer
(B) \((51,99)\)
Step-by-step Solution
Detailed explanation
B.\((51,99)\)
Comparing atomic number,
\[
\begin{aligned}
92 =x+41 \\
x =92-41 \\
x =51
\end{aligned}
\]Comparing atomic mass number, \(235+1=133+y+4\)
\[
\begin{aligned}
236 =137+y \\
y =236-137=99
\end{aligned}
\]
Comparing atomic number,
\[
\begin{aligned}
92 =x+41 \\
x =92-41 \\
x =51
\end{aligned}
\]Comparing atomic mass number, \(235+1=133+y+4\)
\[
\begin{aligned}
236 =137+y \\
y =236-137=99
\end{aligned}
\]
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