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GUJCET · Physics · Nuclei

Find the value of \(x\) and \(y\) in the following nuclear reaction.
\({ }_{92}^{235} \mathrm{U}+{ }_0^1 n \rightarrow{ }_x^{133} \mathrm{Sb}+{ }_{41}^y \mathrm{Nb}+4{ }_0^1 n\)

  1. A \((51,95)\)
  2. B \((51,99)\)
  3. C \((92,1)\)
  4. D \((133,41)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((51,99)\)

Step-by-step Solution

Detailed explanation

B.\((51,99)\)
Comparing atomic number,
\[
\begin{aligned}
92 =x+41 \\
x =92-41 \\
x =51
\end{aligned}
\]Comparing atomic mass number, \(235+1=133+y+4\)
\[
\begin{aligned}
236 =137+y \\
y =236-137=99
\end{aligned}
\]