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GUJCET · Physics · Current Electricity
A voltmeter of a very high resistance is joined in the circuit as shown in figure. The voltage shown by this voltmeter will be ________.
- A 6 V
- B 5 V
- C 2.5 V
- D 3 V
Answer & Solution
Correct Answer
(A) 6 V
Step-by-step Solution
Detailed explanation
A
Both \(8 \Omega\) resistors are connected in parallel to each other.
Equivalent resistance of them
\(R _{e q}=\frac{8 \times 8}{8+8}=4 \Omega\)
Total resistance of circuit
\(R =6+4=10 \Omega\)
Current flowing through circuit
\(\begin{aligned} I & =\frac{V}{R} \\ \therefore \quad I & =\frac{10}{10} \\ \therefore \quad I & =1 A\end{aligned}\)
Voltage shown by voltmeter
\(\begin{aligned} & V = IR ^{\prime} \\ \therefore \quad & V =1 \times 6 \\ \therefore \quad & V=6 V\end{aligned}\)
Both \(8 \Omega\) resistors are connected in parallel to each other.
Equivalent resistance of them
\(R _{e q}=\frac{8 \times 8}{8+8}=4 \Omega\)
Total resistance of circuit
\(R =6+4=10 \Omega\)
Current flowing through circuit
\(\begin{aligned} I & =\frac{V}{R} \\ \therefore \quad I & =\frac{10}{10} \\ \therefore \quad I & =1 A\end{aligned}\)
Voltage shown by voltmeter
\(\begin{aligned} & V = IR ^{\prime} \\ \therefore \quad & V =1 \times 6 \\ \therefore \quad & V=6 V\end{aligned}\)
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