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GUJCET · Physics · Electrostatic Potential and Capacitance
An electron is accelerated through a potential difference of 2.5 V , then energy is gained by an electron is ________.
(Charge of an electron \(1 \times 10^{-19} C\) )
- A 2.5 J
- B 2.5 MeV
- C 2.5 eV
- D 2.5 erg
Answer & Solution
Correct Answer
(C) 2.5 eV
Step-by-step Solution
Detailed explanation
(C)
Energy \(\frac{1}{2} m v_{\max }^2= eV\)
\(\frac{1}{2} m v_{\max }^2=2.5 eV\)
Energy \(\frac{1}{2} m v_{\max }^2= eV\)
\(\frac{1}{2} m v_{\max }^2=2.5 eV\)
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