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GUJCET · Physics · Electric Charges and Fields
An electric dipole with dipole moment \(4 \times 10^{-9} Cm\) is aligned at \(60^{\circ}\) with direction of a uniform electric field of magnitude \(5 \times 10^4 NC ^{-1}\). Calculate the magnitude of the torque acting on the dipole.
- A \(17.3 \times 10^{-6} Nm\)
- B \(1.73 \times 10^{-4} Nm\)
- C \(1.73 \times 10^{-6} Nm\)
- D \(17.3 \times 10^{-4} Nm\)
Answer & Solution
Correct Answer
(B) \(1.73 \times 10^{-4} Nm\)
Step-by-step Solution
Detailed explanation
(B)
\(\begin{array}{l}\tau=p E \sin \theta \\ \tau=4 \times 10^{-9} \times 5 \times 10^4 \times \sin 60^{\circ} \\ \tau=20 \times 10^{-5} \times \frac{\sqrt{3}}{2} \\ \tau=1.73 \times 10^{-4} Nm \end{array}\)
\(\begin{array}{l}\tau=p E \sin \theta \\ \tau=4 \times 10^{-9} \times 5 \times 10^4 \times \sin 60^{\circ} \\ \tau=20 \times 10^{-5} \times \frac{\sqrt{3}}{2} \\ \tau=1.73 \times 10^{-4} Nm \end{array}\)
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