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GUJCET · Physics · Alternating Current
A L-C-R series AC circuit is tuned to resonance. The impedance of the circuit is now ____________ .
- A R
- B \(\left.\left\lvert\, \mathrm{R}^{2}+\left(\frac{1}{\omega \mathrm{C}}-\omega \mathrm{L}\right)^{2}\right.\right]^{\frac{1}{2}}\)
- C \(\left[\mathrm{R}^{2}+(\omega \mathrm{L})^{2}+\left(\frac{1}{\omega \mathrm{C}}\right)^{2}\right]^{\frac{1}{2}}\)
- D \(\left.\left\lvert\, \mathrm{R}^{2}+\left(\omega \mathrm{L}-\frac{1}{\omega \mathrm{C}}\right)^{2}\right.\right\}^{\frac{1}{2}}\)
Answer & Solution
Correct Answer
(A) R
Step-by-step Solution
Detailed explanation
(A) \(R\)
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