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GUJCET · Physics · Moving Charges and Magnetism
10 A current is passing through a very long wire of radius 5 cm . Then magnetic field at a distance of 2 cm insides from its curved surface is _________ \(\times 10^{-5} T\).
- A 2.4
- B 6.7
- C 4.4
- D 3.4
Answer & Solution
Correct Answer
(A) 2.4
Step-by-step Solution
Detailed explanation
A
Magnetic field at a distance of 2 cm from the curved surface i.e. 3 cm from the axis.
\(\begin{array}{l}B=\frac{\mu_0 I r}{2 \pi R^2} \\B=\frac{4 \pi \times 10^{-7} \times 10 \times 3 \times 10^{-2}}{2 \pi \times\left(5 \times 10^{-2}\right)^2} \\B=2.4 \times 10^{-5} T\end{array}\)
Magnetic field at a distance of 2 cm from the curved surface i.e. 3 cm from the axis.
\(\begin{array}{l}B=\frac{\mu_0 I r}{2 \pi R^2} \\B=\frac{4 \pi \times 10^{-7} \times 10 \times 3 \times 10^{-2}}{2 \pi \times\left(5 \times 10^{-2}\right)^2} \\B=2.4 \times 10^{-5} T\end{array}\)
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