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GUJCET · Physics · Electrostatic Potential and Capacitance
Two plates are 20 cm apart and a potential difference of 10 V is applied between them. The electric field between the plates is _______.
- A \(0.5 Vm ^{-1}\)
- B \(20 Vm ^{-1}\)
- C \(50 Vm ^{-1}\)
- D \(500 Vm ^{-1}\)
Answer & Solution
Correct Answer
(C) \(50 Vm ^{-1}\)
Step-by-step Solution
Detailed explanation
(C)
\(\begin{array}{l} E =\frac{ V }{d} \\ E =\frac{10}{20 \times 10^{-2}} \\ E =50 Vm ^{-1}\end{array}\)
\(\begin{array}{l} E =\frac{ V }{d} \\ E =\frac{10}{20 \times 10^{-2}} \\ E =50 Vm ^{-1}\end{array}\)
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