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GUJCET · Chemistry · Chemical Kinetics
In a reaction \(A \rightarrow B\), if the concentration of reactant is increased by 9 times then rate of reaction increases 3 times. What is the order of reaction?
- A \(\frac{1}{3}\)
- B \(\frac{1}{2}\)
- C 3
- D 2
Answer & Solution
Correct Answer
(B) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
B
For \(A \rightarrow B\)
Rate law \(=k[A]^{1 / 2}\)
If concentration is increase 9 times and Rate by 3 times so order of reaction must be \(1 / 2\).
For \(A \rightarrow B\)
Rate law \(=k[A]^{1 / 2}\)
If concentration is increase 9 times and Rate by 3 times so order of reaction must be \(1 / 2\).
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