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GUJCET · Maths · Vector Algebra
Vector \(\vec{x}\) is a vector in the direction of \((2,-2,1)\) and having magnitude of 6 unit. Vector \(\vec{y}\) is a vector in the direction of \((1,1,-1)\) and having magnitude of \(\sqrt{3}\) units then, \(|\vec{x}+2 \vec{y}|=\) _________ ) .
- A 40
- B \(\sqrt{35}\)
- C \(\sqrt{17}\)
- D \(2 \sqrt{10}\)
Answer & Solution
Correct Answer
(D) \(2 \sqrt{10}\)
Step-by-step Solution
Detailed explanation
\(\vec{x} = 6 \frac{(2,-2,1)}{\sqrt{2^2+(-2)^2+1^2}} = 6 \frac{(2,-2,1)}{3} = (4,-4,2)\) \(\vec{y} = \sqrt{3} \frac{(1,1,-1)}{\sqrt{1^2+1^2+(-1)^2}} = \sqrt{3} \frac{(1,1,-1)}{\sqrt{3}} = (1,1,-1)\)
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