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GUJCET · Maths · Integrals
If \(\int\left\{\cos ^{-1} x-\left(1-x^2\right)^{-\frac{1}{2}}\right\} k d x=k \cdot \cos ^{-1} x+c\) then \(k=\) _________ .
- A \(e^{\cos ^{-1} x}\)
- B \(e^x\)
- C \(e^{-x}\)
- D \(-e^x\)
Answer & Solution
Correct Answer
(B) \(e^x\)
Step-by-step Solution
Detailed explanation
\(\frac{d}{dx} \left[ \int\left\{\cos ^{-1} x-\left(1-x^2\right)^{-\frac{1}{2}}\right\} k d x \right] = \frac{d}{dx} \left[ k \cdot \cos ^{-1} x+c \right]\) \(k \left( \cos ^{-1} x - \left(1-x^2\right)^{-\frac{1}{2}} \right) = \frac{dk}{dx} \cos ^{-1} x + k \left( -\left(1-x^2\right)^{-\frac{1}{2}} \right)\)
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