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GUJCET · Maths · Integrals

If \(\int\left\{\cos ^{-1} x-\left(1-x^2\right)^{-\frac{1}{2}}\right\} k d x=k \cdot \cos ^{-1} x+c\) then \(k=\) _________ .

  1. A \(e^{\cos ^{-1} x}\)
  2. B \(e^x\)
  3. C \(e^{-x}\)
  4. D \(-e^x\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(e^x\)

Step-by-step Solution

Detailed explanation

\(\frac{d}{dx} \left[ \int\left\{\cos ^{-1} x-\left(1-x^2\right)^{-\frac{1}{2}}\right\} k d x \right] = \frac{d}{dx} \left[ k \cdot \cos ^{-1} x+c \right]\) \(k \left( \cos ^{-1} x - \left(1-x^2\right)^{-\frac{1}{2}} \right) = \frac{dk}{dx} \cos ^{-1} x + k \left( -\left(1-x^2\right)^{-\frac{1}{2}} \right)\)